-12x^2-16x-5=0

Solution for -12x^2-16x-5=0 equation:

-12x^2-16x-5=0

a = -12; b = -16; c = -5;
Δ = b2-4ac
Δ = -162-4·(-12)·(-5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*-12}=\frac{12}{-24}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*-12}=\frac{20}{-24}
=-5/6
$